posted by Shadow on .
How many moles of ion are in the following?
A. 0.0200 g AgNO3
- Could someone give me the step to solve such problems? Thanks
How many mols AgNO3 do you have? That's mols = grams/molar mass
Then you have that many mols Ag^+ and that many mols NO3^-
Since the AgNO3 have a molar mass of 169.87 g. I divided that by 0.02 g and got 0.000118 moles of AgNO3. How would I find how many moles is Ag and how many is NO3? Thanks
I mean Ag but not NO3 **
No, you divided 0.02 by 169.87 to obtain 0.000118 mols AgNO3.
So you have 0.000118 mols Ag^+ and 0.000118 mols NO3^-
The formula tells you that you have 1 mol Ag^+ per mol AgNO3 and 1 mol NO3^- per mol AgNO3. Total mols of ions (which is what I think the original post asked for) is 0.000118 + 0.000118 = ?
It would be 0.00023 mol .Thank you. Let say if they want to know the amount of ions. I would just have to multiply that number by avogadro number right? Thanks
Yes, but you are throwing s.f. away.
0.000118 + 0.000118 = 0.000236 and that x 6.02E23 = total ions.