Posted by **Jo** on Tuesday, January 29, 2013 at 9:31pm.

Denise's cell phone plan is $29.95 per month plus $.10 per minute for each minute over 300 minutes of call time. Denise's cell phone bill is $99.95. For how many minutes was she billed? Answer is 700 but what is the algebraic equation?

- Algebra Problem Solving -
**Reiny**, Tuesday, January 29, 2013 at 10:47pm
cost = .10(m-300) + 29.95 , where m is the number of minutes

so ....

.10(m-300) + 29.95 = 99.95

.1m - 30 = 70

.1m = 100

m = 100/.1 = 1000

She used 1000 minutes, but is only billed for any time over 300 minutes , look at (m-300) in the equation.

She was billed for 700 minutes

btw, the equation is only valid for m>300

if m<300

it would simply be

cost = 29.95

## Answer This Question

## Related Questions

- algebra - I need to write an equation for the following: Denise's cell phone ...
- Algebra ASAP - I a working wth a cell phone performance task project. I have to ...
- math - 73. Cell Phone Plan A cell phone plan costs $3.95 per month plus $0.07 ...
- math - Verizon has a cell phone plan for $28.00 per month plus $.30 per minute ...
- Geometry - Horizon has a cell phone plan for $28.00 per month plus $.30 per ...
- Math ASAP - Verizon has a cell phone plan for $28.00 per month plus $.30 per ...
- pre-albegra word problem - I need to write a verbal rule to determine the total ...
- Math - I have the same problem as Marita. Can someone tell us what equation to ...
- Algebra Please! - Posted by Thomas M on Monday, March 9, 2015 at 4:12am. I am ...
- math - A cell phone company charges by the minute (and partial minute) for a ...

More Related Questions