Posted by Anon on Tuesday, January 29, 2013 at 9:22pm.
The boiling point of an aqueous solution is 102.48 °C. What is the freezing point?
I know that formula for freezing point is delta Tf = Kf*m but what do I plug in for each?
Chemistry - DrBob222, Tuesday, January 29, 2013 at 10:11pm
delta T = Kb*m
Substitute and solve for m
Then plug m and Kf into your delta T = Kf*m formula and solve for delta T, then freezing point.
Chemistry - Anon, Tuesday, January 29, 2013 at 10:37pm
Is the freezing point 372 degree C?
Kb = 0.512
Kf = 1.86
Chemistry - DrBob222, Tuesday, January 29, 2013 at 11:19pm
When you do this you should show your work. I can tell at a glance where your trouble is.
For boiling point data:
delta T =Kb*m
(102.48-100) = 0.512*m
m = about 4.84m
Then delta T = Kf*m
dT = 1.86*4.84
dT = about9.00 = about 9.00 degrees lower than the normal freezing point.
0-9.00 = -9.00 C.
Chemistry - lola, Friday, May 22, 2015 at 1:39pm
Answer This Question
More Related Questions
- Chemistry problem - What is the expected freezing point of a 3.50 m aqueous ...
- Chemistry - Calculate the boiling points of freezing points of the following ...
- chemistry - Which of the following statements about boiling points are true? A. ...
- chemistry - The freezing point of a 0.010 m aqueous solution of a nonvolatile ...
- Chemistry - The boiling point of an aqueous solution is 102.35 °C. What is the ...
- Chemistry - The equation for lowering the freezing point of a solvent is given ...
- Chemistry - What Occurs as a salt dissolves in water? the number of ions in the ...
- chemistry - What is the expected freezing point of a 3.50 m (m standing for ...
- chemistry - The boiling point of an aqueous solution is elevated by 0.15 degrees...
- Physical Chemistry - When 1.33 g of a nonpolar solute was dissolved in 50.0 g of...