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February 1, 2015

February 1, 2015

Posted by **Makella** on Tuesday, January 29, 2013 at 8:38pm.

Can someone help me with this? I don't understand how to do the y=-14 part my teacher didn't explain it to us today.

- Geometry -
**Reiny**, Tuesday, January 29, 2013 at 9:04pmObviously I cannot help you with the graphing, but

I assume you can do the reflection about the x-axis

(any point on the x-axis would stay, all points keep their x's, and their y's become opposite.

e.g. A(6,8) ---> A1(6,-8)

repeat for the other points and graph the new figure, then shade as instructed.

y = -14 is simply a horizontal line 14 units below the x-axis (two points on it would be (5,-14) and (-5,-14) , join them)

Now you are reflecting all points around that line

the x's would stay the same, but for the y, calculate how far above -14 it is, then move down just as far below the -14

e.g. B(12,4) is 18 units above the line y = -14

(how did I get 18 ??)

so it moves 18 units below that line, as a result:

B(12,4) ---> B2(12,-32)

you can check your new points are correct by taking the average of your y values of the old point and the new point, you should get -14

(-32 + 4)/2 = -14

give it a try, I suggest you print out my instructions.

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