Posted by hana on Tuesday, January 29, 2013 at 8:22pm.
Just add the two vectors.
The eastward displacement is
X = 100 + 50 cos35 = 140.96 miles
The northern displacement (assuming north is positive) is
Y = -50 sin35 = -28.68 miles
(The minus sign is there because the second vector is south of east, not north).
Total displacementis
= sqrt[(140.96)^2 + (-28.68)^2]
The direction(measured south of east) is tan^-1 (28.68/140.96) = 11.5 degrees
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