Posted by **Brownie** on Tuesday, January 29, 2013 at 5:59pm.

A particle is projected along an inclined plane with a velocity given by the formula

v = 4.4t2 + 10.1t -23.2. Determine the acceleration of the particle when t = 1.5 s.

acceleration in m/s2 =

My Answer

V'=8.8t+10.1

V"=8.8

V"(1.5)= 8.8

acceleration in m/s2 = 8.8

Can you please confirm this is correct.

Thanks

## Answer This Question

## Related Questions

- physics - The position of a particle moving along an x axis is given by x = 15t2...
- calculus - 5. A particle moves along the x-axis in such a way that its position ...
- Physics - A particle starts from the origin at t = 0 and moves along the ...
- Calculus - The position of a particle moving on a horizontal line is given by s(...
- math - A particle moves along straight line such that its displacement S meters...
- physics - A particle moves in the xy plane with constant acceleration. At time ...
- Physics - a Particle in x-y plane with const acceleration of 1.5m/s sq. in the ...
- calculus - 5. A particle moves along the y – axis with velocity given by v(t)=...
- science - the velocity of a particle is given by v=[16t^2i+4t^3j +(5t+2)k]m/s, ...
- math - A particle is traveling along a one-dimensional path (such as a number ...

More Related Questions