Posted by Brownie on .
Given v = 2t3 + 87t2  636, determine the acceleration for t= 1 s.
acceleration in m/s2 =
My Answer
v'= 6t^2+174t
V"= 12t
V"(1) = 12
acceleration in m/s2 = 12
Can you please confirm this is correct..
Thanks!

Math  check answer 
Henry,
V' = 6t^2 + 174t
V" = 12t + 174.