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January 30, 2015

January 30, 2015

Posted by **Mohamed** on Tuesday, January 29, 2013 at 1:15pm.

This is how I've done it P(B)=0.70, P(J)=0.70. Then from the third piece of info I have P(B given (J U J')) but that doesn't seem to make sense to me because Bob being correct isn't affected by Jane being correct or not? So is the third statement just P(B n J) + P(B n J') = 0.60 but then isn't that just P(B) which is not 0.60 but 0.70?

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