Monday

March 30, 2015

March 30, 2015

Posted by **Mohamed** on Tuesday, January 29, 2013 at 1:15pm.

This is how I've done it P(B)=0.70, P(J)=0.70. Then from the third piece of info I have P(B given (J U J')) but that doesn't seem to make sense to me because Bob being correct isn't affected by Jane being correct or not? So is the third statement just P(B n J) + P(B n J') = 0.60 but then isn't that just P(B) which is not 0.60 but 0.70?

**Answer this Question**

**Related Questions**

Statistics - On a very short quiz, there is one multiple choice question with 5 ...

Business Statistics - John & Jane are married. The probability that John watches...

Economics - If Jane can produce 3 pairs of shoes hourly, while Bob can produce 2...

English - 1. Jane and Mike are the same in score. Jane and Mike are the same in ...

english - hey can u help me with punctuations are these correct> having ...

Math - Consider a game where Ann and Bob play against each other in a dice game...

Math/Probability - Anna and bob play a game in which Anna begins by rolling a ...

Math check and question - x is a binomial random variable. (Give your answers ...

Math - Anna and bob play a game in which Anna begins by rolling a fair dice, ...

math - If A, then B is equivalent to If not B, then not A Not (A and B) is ...