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March 31, 2015

March 31, 2015

Posted by **Ashley** on Tuesday, January 29, 2013 at 11:52am.

area in m2 =

can anyone shed some light on this questions....

- Math -
**Steve**, Tuesday, January 29, 2013 at 12:37pmBasically you want the smallest area bounded by the x- and y-axes, and any line passing through (65,55).

A line through (65,55) with slope m will have intercepts at y = 55-65m and x=65+55/m

So, the area of the enclosed triangle is

a(m) = 1/2 (55+65m)(65+55/m)

a(m) = 25/2m (11-13m)^2

da/dm = 25/2 (121/m^2 - 169)

da/dm=0 when m = ±11/13

We know we need a negative slope, so m = -11/13

The minimum area is thus 7150

- Math -
**Steve**, Tuesday, January 29, 2013 at 12:37pmoops on typos

That should be 1/2 (55-65m)(65-55/m)

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