Posted by **Chanelle** on Tuesday, January 29, 2013 at 11:36am.

Suppose that you have a supply of a 25% solution of alcohol and a 75% solution of alcohol. How many quarts of each should be mixed to produce 90 quarts that is 60% alcohol?

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**Steve**, Tuesday, January 29, 2013 at 11:42am
work with the amount of alcohol in each part. It has to add up to the total alcohol.

.25x + .75(90-x) = .60(90)

x = 27

so, 27 qt @ 25% and 63 qt @ 75%

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**Chanelle**, Tuesday, January 29, 2013 at 11:47am
Thank you,and how did you get come up with the equation?

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**Chanelle**, Tuesday, January 29, 2013 at 11:49am
Thank you,and how did set up the equation?

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**Steve**, Tuesday, January 29, 2013 at 12:14pm
If you let x be the amount of 25% solution, then .25x is the amount of alcohol in that solutions.

Since there are 90 qts in all, 90-x is the amount of the 75% solution. .75(90-x) is the amount of alcohol in that solution.

Add up the two amounts of alcohol, and it must equal the amount of alcohol in 90 qts of 60% solution.

Ta-daa

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**Chanelle**, Tuesday, January 29, 2013 at 12:41pm
Thanks

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