Posted by Chanelle on Tuesday, January 29, 2013 at 10:42am.
Suppose that Maria has 140 coins consisting of pennies, nickels, and dimes. The number of nickels she has is 12 less than twice the number of pennies; the number of dimes she has is 22 less than three times the number of pennies. How many coins of each kind does she have?

Intermediate Algebra  Steve, Tuesday, January 29, 2013 at 11:17am
p+n+d = 140
n = 2p12
d = 3p22
(p,n,d) = (29,46,65)

Intermediate Algebra  Chanelle, Tuesday, January 29, 2013 at 11:30am
Thank you !
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