Posted by **Chanelle** on Tuesday, January 29, 2013 at 10:42am.

Suppose that Maria has 140 coins consisting of pennies, nickels, and dimes. The number of nickels she has is 12 less than twice the number of pennies; the number of dimes she has is 22 less than three times the number of pennies. How many coins of each kind does she have?

- Intermediate Algebra -
**Steve**, Tuesday, January 29, 2013 at 11:17am
p+n+d = 140

n = 2p-12

d = 3p-22

(p,n,d) = (29,46,65)

- Intermediate Algebra -
**Chanelle**, Tuesday, January 29, 2013 at 11:30am
Thank you !

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