Posted by Ashley on Tuesday, January 29, 2013 at 8:45am.
Would it be safe to say that the the diagonal line in the rectangle could equal r = 2.
so I could use
b^2+ h^2 =r^2
solve for h
h= Square root ( r^2 -b^2)
Area = b^2 * Square root (r^2-b^2)
area = b*(r^2-b^2)^1/2 ....... ????
Ok
ok....
so is next step take the first derv of the area
Area of rect '= -1/2(4-b^2) + (4-2^2)^1/2
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