maths
posted by tuhituhi .
if x and y vary inversely and x=18 when y=8,find x when y=16

x and y vary inversely y = kx , where k is a constant
given: x=18, y = 8
8 = 18k
k = 4/9
so y = (4/9)x or 9x = 4y
when y = 16
9x = 4(16)
x = 64/9
or
x1/y1 = y2/x2
18/8 = 16/x2
18x2 = 8(16)
x2 = 8(16)/18 = 64/9 
eh? inversely ==> xy = k
8*18 = k
k = 144
when y=16,
x*16 = 144
x = 9