Posted by Anonymous on Tuesday, January 29, 2013 at 7:32am.
Find the derivative of 2x+3/ 3x2
using first principle method.

maths  Reiny, Tuesday, January 29, 2013 at 8:19am
you meant:
f(x) = y = (2x+3)/(3x2)
so f(x+h) = (2x + 2h + 3)/(3x + 3h  2)
dy/dx = lim [ (2x+2h+3)/(3x+3h2)  (2x+3)/(3x2) ]/h , as h >0
= lim [ ((2x + 2h + 3)(3x2)  (2x+3)(3x+3h+2))/((3x+3h2)(3x+h))]/h
= lim [ (5h/((3x+3h2)(3x2))]/h , as h >0
= lim 5/((3x+3h2)(3x2)) , as h >0
= 5/(3x2)^2
Answer This Question
Related Questions
 Calculus using the first derivative  Y=e^x differentiate using the first ...
 Applied Calculus  Find the first and second derivative of the function: x/(7x+...
 math  find the local maximum and minimum values of f using both the first and ...
 calculus  find the local maximum and minimum values of f using both the first ...
 math  For what intervals is g(x) = 1/x2 + 1 concave down? (Enter your answer ...
 maths  solve using first principle of differenciation 1)y=e^3x 2)y=1/3(x^2)^1/2
 maths  solve using first differenciation principle 1)y=e^sinx
 maths  solve using first principle of differenciation 1)y=sin{square root(x)}
 Calculus  derivatives  Okay, I want to find the derivative of (x^x)^(x^x)... ...
 chemistry  Why is the second derivative of a titration curve more accurate ...
More Related Questions