Posted by Anonymous on Tuesday, January 29, 2013 at 7:32am.
you meant:
f(x) = y = (2x+3)/(3x-2)
so f(x+h) = (2x + 2h + 3)/(3x + 3h - 2)
dy/dx = lim [ (2x+2h+3)/(3x+3h-2) - (2x+3)/(3x-2) ]/h , as h --->0
= lim [ ((2x + 2h + 3)(3x-2) - (2x+3)(3x+3h+2))/((3x+3h-2)(3x+h))]/h
= lim [ (5h/((3x+3h-2)(3x-2))]/h , as h -->0
= lim 5/((3x+3h-2)(3x-2)) , as h -->0
= 5/(3x-2)^2
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