Posted by **Ashley** on Tuesday, January 29, 2013 at 6:10am.

The power P delivered to a load by a current of i amperes through a resistance of 19 ohms, when 110 volts are supplied at one end of the line, is given by the formula P = 110i - 19i2 . Determine the maximum power that can be delivered.

maximum power in watts =

- Math -
**Writeacher**, Tuesday, January 29, 2013 at 7:16am
Your umpteen posts have been removed.

Once you write up **YOUR ATTEMPT** at each problem, please re-post, and someone here will be happy to comment.

- Math -
**Ashley**, Tuesday, January 29, 2013 at 8:15am
Oh, sorry I didn't realise that I needed to provide my answer. I just want to check to see if I obtain the correct answer.

My answer is:

P=110i-19i^2

P'=110-38i

0=110-38i

i=2.8947

P"=-38 therefore a max

Max Power in watts = 2.8947

- Math -
**Writeacher**, Tuesday, January 29, 2013 at 8:26am
Please re-post your questions along with your answers, and a math teacher will check your work.

Also there's no need to switch user names.

- Math -
**bobpursley**, Tuesday, January 29, 2013 at 12:54pm
Hmmm. I agree with i at 2.89 amps

Powermax=put i in the formula for power given, and you have it.

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