Posted by Gabriel Dungca on Monday, January 28, 2013 at 11:55pm.
Both threads hang at an angle sin^-1 10/100 = 5.74 degrees from vertical.
The ratio of the vertical weight force to the horizontal repulsive Coulomb force is
tan5.74
= [k*Q1*Q2/(0.20)^2]/(M*g)
= 0.1005
k is the Coulomb constant. You may need to look this up.
Q1 = -0.6*10^-6 C
M = 0.015 kg
Solve for Q2. It will also be a negative charge.
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