Monday

January 26, 2015

January 26, 2015

Posted by **Jack** on Monday, January 28, 2013 at 11:31pm.

h->0

I have 1 as my final answer and was wondering if i was correct

- Calculus -
**Steve**, Tuesday, January 29, 2013 at 11:12amHmmm. As h-> 0,

1/(1+h)^2 -> 1

1/h -> ∞

so the limit is 1-∞ = -∞

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