Homework Help: Physics

Posted by Sadi on Monday, January 28, 2013 at 11:03pm.

A 250-kg crate is being pushed across a horizontal floor by a force P that makes an angle of 30.8 ° below the horizontal. The coefficient of kinetic friction is 0.224. What should be the magnitude of P, so that the net work done by it and the kinetic frictional force is zero?

Thus far, I know Pcos(30.8) = fk, where fk= (0.224)(mg+Psin(30.8)). I am not sure, however, how I can solve for the magnitude of the P.

Physics - bobpursley, Monday, January 28, 2013 at 11:08pm
no, if the force is pushing up, the term in vertical forces is mg-PSin(angle)

P cosTheta=.224(mg-PsinTheta)

Now, you know that for net work to be zero, friction has to be zero. which means mg-PsinTheta=0
solve for P

Answer this Question

Related Questions

physical aspects of nature - A 1,440-N crate is being pushed across a level ...
Physics - A 1.60 102-kg crate is being pushed across a horizontal floor by a ...
physics - A 1.20*10^2 kg crate is being pushed across a horizontal floor by a ...
ap physics - A 1.20*10^2 kg crate is being pushed across a horizontal floor by a...
Physics - A 1.00e2kg crate is being pushed across a horizontal floor by a force ...
physics - A 1,040-N crate is being pushed across a level floor at a constant ...
physics - A 1100 N crate is being pushed across a level floor at a constant ...
physics - A 1,440-N crate is being pushed across a level floor at a constant ...
physics - A 1,080-N crate is being pushed across a level floor at a constant ...
Physics - A 1200-N crate is being pushed across a level floor at a constant ...

For Further Reading

First Name:
School Subject:
Answer: