Posted by **lee** on Monday, January 28, 2013 at 10:32pm.

An athlete executing a long jump leaves the ground at a 32.3 angle and travels 7.84 m. What was the takeoff speed?

If this speed were increased by just 5.0%, how much longer would the jump be?

- physics -
**bobpursley**, Monday, January 28, 2013 at 10:59pm
Neglecting air friction? Right.

vertical component speed=Vsin32.2

time in air..

hf=hi+vv*t-4.9t^2

0=V *sin32.2 t-4.9t^2

t=V *sin32.2/4.9

now, knowing the time in air, distance traveled is

7.84 =V*Cos32.2 * t solve for V given t above.

- physics -
**Anonymous**, Sunday, June 14, 2015 at 10:40pm
9.41m/s

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