Posted by lee on Monday, January 28, 2013 at 10:32pm.
An athlete executing a long jump leaves the ground at a 32.3 angle and travels 7.84 m. What was the takeoff speed?
If this speed were increased by just 5.0%, how much longer would the jump be?

physics  bobpursley, Monday, January 28, 2013 at 10:59pm
Neglecting air friction? Right.
vertical component speed=Vsin32.2
time in air..
hf=hi+vv*t4.9t^2
0=V *sin32.2 t4.9t^2
t=V *sin32.2/4.9
now, knowing the time in air, distance traveled is
7.84 =V*Cos32.2 * t solve for V given t above.

physics  Anonymous, Sunday, June 14, 2015 at 10:40pm
9.41m/s
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