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An athlete executing a long jump leaves the ground at a 32.3 angle and travels 7.84 m. What was the takeoff speed?
If this speed were increased by just 5.0%, how much longer would the jump be?

  • physics -

    Neglecting air friction? Right.

    vertical component speed=Vsin32.2
    time in air..
    0=V *sin32.2 t-4.9t^2
    t=V *sin32.2/4.9

    now, knowing the time in air, distance traveled is
    7.84 =V*Cos32.2 * t solve for V given t above.

  • physics -


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