physics
posted by lee .
An athlete executing a long jump leaves the ground at a 32.3 angle and travels 7.84 m. What was the takeoff speed?
If this speed were increased by just 5.0%, how much longer would the jump be?

Neglecting air friction? Right.
vertical component speed=Vsin32.2
time in air..
hf=hi+vv*t4.9t^2
0=V *sin32.2 t4.9t^2
t=V *sin32.2/4.9
now, knowing the time in air, distance traveled is
7.84 =V*Cos32.2 * t solve for V given t above. 
9.41m/s