Posted by rose on Monday, January 28, 2013 at 9:55pm.
0.1M NaOH = 0.1N NaOH
H2A + 2NaOH ==> Na2A + 2H2O
When the problem says "complete" neutralization, that mans BOTH H atoms have been replaced.
mL x N x m.e.w = grams.
50.00 x 0.1N x m.e.w. = 0.240g
solve for m.e.w = milliequivalent weight.
Multply by 1000 to convert to equivalent weight.
Then equivalent weight = molecular weight/replaceable Hs.
You know equivalent weight and replaceable H atoms (2), solve for molecular weight.
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