Upon decomposition, one sample of magnesium fluoride produced 1.66kg of magnesium and 2.56kg of fluorine. A second sample produced 1.25kg of magnesium.How much fluorine (in grams) did the second sample produce?

...........MgF2 ==> Mg + F2

sample 1...4.22....1.66..2.56
sample 2...........1.25...?
? = 2.56 x 1.25/1.66 = ?g F2

1927

2.34

To find the amount of fluorine produced by the second sample of magnesium fluoride, we first need to determine the ratio of magnesium to fluorine in the compound.

From the information given about the first sample, we can see that 1.66kg of magnesium produced 2.56kg of fluorine. This means that 1kg of magnesium produces (2.56kg / 1.66kg) = 1.545kg of fluorine.

Now, we can use this ratio to find the amount of fluorine produced by the second sample. We are told that the second sample produced 1.25kg of magnesium. So, we can calculate:

Amount of fluorine = Amount of magnesium * Ratio of fluorine to magnesium
= 1.25kg * 1.545kg/kg = 1.93125kg

To express this amount in grams, we multiply by 1000 (since there are 1000g in 1kg):

Amount of fluorine in grams = 1.93125kg * 1000g/kg = 1931.25g

Therefore, the second sample of magnesium fluoride produced 1931.25 grams of fluorine.