Posted by **Anonymous** on Monday, January 28, 2013 at 1:16pm.

Evaluate the definite integral from 0 to 1 of

(x^2)sqrt(5x+6)dx

- Calc 2 -
**Steve**, Monday, January 28, 2013 at 4:48pm
∫[0,1] x^2 √(5x+6) dx

That's almost x^5/2, but for that pesky 5x+6. So, let u=5x+6 and we have x = (u-6)/5:

∫[6,11] (u-6)^2/25 √u du/5

= 1/125 ∫[6,11] u^(5/2) - 12u^(3/2) + 36u^(1/2) du

= 1/125 (2/7 u^7/2 - 24/5 u^5/2 + 24u^3/2)[6,11]

= 2/4375 (576√6 - 1111√11)

= 1.03948

## Answer this Question

## Related Questions

- Calc. - Evaluate the definite integral. S b= sqrt(Pi) a= 0 xcos(x^2)dx I'm not ...
- calculus (please with steps and explanations) - consider the function f that is ...
- calc check: curve length - Find the length of the curve y=(1/(x^2)) from ( 1, 1...
- Math - Evaluate the following definite integral. sqrt(11 x)(sqrt(x) + sqrt(11)) ...
- Calculus (urgent help) - consider the function f that is continuous on the ...
- Calc - If we know that the definite integral from -6 to -3 of f(x) equals 6, the...
- calculus - consider the function f that is continuous on the interval [-5,5] and...
- calc - i need to find the definite integral from 0 to 2|b| of .... x divided by ...
- Calc. - Evaluate the indefinite integral. Please check my work? Not sure if I am...
- Calc - Evaluate the definite integral: int_{ 2 } ^ { 7 } (10 x + 5) dx =

More Related Questions