A glass ball, ball A, of mass 6.0 g moves at a velocity of 18.0 cm/s. It collides with a second ball, ball B, of mass 8.0 g, moving along the same line of velocity of 11.0 cm/s. After the collision, ball A is still moving, but with a velocity of 10.0 cm/s.

Ball A's original momentum:
.00108 kg·m/s

Ball A's change in momentum?
-4.8E-4 kg·m/s

Ball B's change in momentum?
4.8E-4 kg·m/s

Ball B's speed after the collision?
17 cm/s

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What is the momentum of ball B after the collision?
__?__ kg·m/s

To find the momentum of ball B after the collision, we need to use the principle of conservation of momentum. According to this principle, the total momentum of the system before the collision is equal to the total momentum of the system after the collision.

The initial momentum of ball A can be calculated by multiplying its mass and initial velocity:
Initial momentum of ball A = mass of ball A * initial velocity of ball A

Given that the mass of ball A is 6.0 g (or 0.006 kg) and the initial velocity of ball A is 18.0 cm/s (or 0.18 m/s), we can calculate its initial momentum:
Initial momentum of ball A = 0.006 kg * 0.18 m/s = 0.00108 kg·m/s

To calculate the final momentum of ball B, we need to subtract the change in momentum of ball A from its initial momentum:
Final momentum of ball B = Initial momentum of ball A - Change in momentum of ball A

Given that the change in momentum of ball A is -4.8E-4 kg·m/s (negative because it loses momentum), we can calculate the final momentum of ball B:
Final momentum of ball B = 0.00108 kg·m/s - (-4.8E-4 kg·m/s)
Final momentum of ball B ≈ 0.00156 kg·m/s

Therefore, the momentum of ball B after the collision is approximately 0.00156 kg·m/s.