write the balanced ionic equation of K2CO3+HCl
Not much to it.
K2CO3 + 2HCl = H2CO3 + 2KCl
But H2CO3, or carbonic acid is just carbonated water, and winds up as CO2 + H2O
So, you wind up with salty fizzy water which then goes flat.
To write the balanced ionic equation for the reaction between potassium carbonate (K2CO3) and hydrochloric acid (HCl), you need to first identify the ions that are present in each compound.
K2CO3 dissociates into two potassium ions (K+) and one carbonate ion (CO3^2-) in solution. HCl dissociates into one hydrogen ion (H+) and one chloride ion (Cl-) in solution.
Now, let's write the balanced ionic equation step by step:
Step 1: Write the dissociation of the reactant compounds:
K2CO3 (aq) → 2K+ (aq) + CO3^2- (aq)
HCl (aq) → H+ (aq) + Cl- (aq)
Step 2: Identify the products that will be formed when the ions combine in the reaction:
K+ (aq) + Cl- (aq) → KCl (aq)
H+ (aq) + CO3^2- (aq) → H2O (l) + CO2 (g)
Step 3: Write the balanced ionic equation, which includes all the ions involved in the reaction:
2K+ (aq) + CO3^2- (aq) + 2H+ (aq) + 2Cl- (aq) → 2KCl (aq) + H2O (l) + CO2 (g)
This is the balanced ionic equation for the reaction between potassium carbonate and hydrochloric acid. It shows the reactant ions combining to form the product ions. It is important to note that balancing the equation ensures that the total charge on both sides of the equation is the same and that the number of atoms of each element is conserved.