posted by Anonymous on .
A 0.35 m2 coil with 50 turns produces a maximum emf of 45 volts in a magnetic field of 0.4 Tesla. What is the speed of rotation of the coil?
Can you show the steps too so I can understand? Thanks
ε=dÔ/dt = d(NBAcosωt)/dt =
= - NBAω sinωt,
ε(max) = NBAω =>
ω=ε(max)/ NBA =45/50•0.4•0.35 =6.43 rad/s