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September 30, 2014

September 30, 2014

Posted by **Jessie** on Monday, January 28, 2013 at 12:01pm.

followed by stretching the resulting graph by a factor of 19.6.

- Calculus -
**Jessie**, Monday, January 28, 2013 at 12:06pmI found the answer to the question below, but I am not sure how it is supposed to differ from the one above?

Write an equation for a graph obtained by vertically stretching the

graph of y = x2 + 10 by a factor of 19.6, followed by a

vertical shift downward by 35 units.

- Calculus -
**Jessie**, Monday, January 28, 2013 at 12:07pm(rewritten) I found the answer to the question below, but I am not sure how it is supposed to differ from the one above?

Write an equation for a graph obtained by vertically stretching the

graph of y = x^2 + 10 by a factor of 19.6, followed by a

vertical shift downward by 35 units.

- Calculus -
**Steve**, Monday, January 28, 2013 at 12:51pmThere's quite a difference between "shifting and stretching" and "stretching and shifting"

In the first case, the shift is also stretched.

For example, if you have a parabola y=x^2, if you stretch first, the graph still touches (0,0), no matter how far it is stretched. If it's then shifted, the stretched parabola is moved by that an=mount.

If it is shifted say, 5 units down, then after stretching by 3, the vertex is now 15 units down.

So, with that parabola,

stretch3-shift5: x^2 -> 3x^2 -> 3x^2-5

shift5-stretch3: x^2 -> x^2-5 -> 3(x^2-5) = 3x^2-15

Now apply that logic to your problem.

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