Posted by Jessie on Monday, January 28, 2013 at 11:57am.
There's no such thing as "third square root". There's "square root", "cube root", "fourth root", etc.
g(h) = ∛h+1 = ∛(4x^2+2x+2)+1
h(g) = 4g^2 + 2g + 2
= 4(∛x+1)^2 + 2(∛x+1) + 2 = 4∛x^2 + 10∛x + 8
h(h) = 4h^2 + 2h + 2
= 4(4x^2 + 2 x + 2)^2 + 2(4x^2 + 2 x + 2) + 2
= 64x^4 + 64x^3 + 88x^2 + 36x + 22
g(x)+1 = (∛x+1)+1 = ∛x + 2
g(x+1) = ∛(x+1) + 1
Related Questions
calculus - prove that d/dx 4x .√(x + √x) = 6x+5 (x)1/2/&...
math - I tried solving these problems and get stuck . Can you please tell me ...
algebra 2 - i need help with these questions simplify √4x^2/y^3 &#...
Calculus - How to rationalize this question? (√3 - √2)/(&...
MATH/ALGEBRA - SOLVE: ã(4x+ 5) + 1 = 0 ã(4x+ 5)= -1...
Math - I have a problem that states to simplify. The equation is d=sqrt(x^2+(4-x...
Math - Find an equation of the line that bisects the obtuse angles formed by the...
Calculus - y=(√x)/((√x)+1) Find the concavity and point of ...
Algebra - How would i complete these problems? 1. (√6mn)^5 2. ^3&#...
Calculus AP need help! - 1. f(x)=√5x+6, find f'(x) 2. f(x)=&#...
For Further Reading
