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July 31, 2014

July 31, 2014

Posted by **Tom** on Monday, January 28, 2013 at 11:22am.

g(x) = interal(a=7x, b=6x) (u+5)/(u-5) du

Hint:

interal(a=7x, b=6x) (u+5)/(u-5) du

= interal(a=0, b=6x) (u+5)/(u-5) du + interal(a=7x, b=0) (u+5)/(u-5) du

- calculus -
**Tom**, Monday, January 28, 2013 at 11:23amit's integral, not interal, sorry for the mistake

- calculus -
**Steve**, Monday, January 28, 2013 at 11:39amUsing Leibnitz's integral rule,

d/dx ∫[7x,6x] (u+5)/(u-5) du

= 6*(6x+5)/(6x-5) - 7*(7x+5)/(7x-5)

= 60/(6x-5) - 70/(7x-5) - 1

- calculus -
**Tom**, Monday, January 28, 2013 at 7:11pmThank Steve. But how do you get 60 or 70?

or the -1?

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