Posted by **natasha** on Monday, January 28, 2013 at 11:18am.

A container holds 2.2 mol of gas. The total average kinetic energy of the gas molecules in the container is equal to the kinetic energy of a 7.7x10-3 kg bullet with a speed of 650 m/s. What is the Kelvin temperature of the gas?

- physics -
**Elena**, Monday, January 28, 2013 at 3:57pm
υ=2.2 mol, N₀=6.022•10²³ mol⁻¹,

k=1.38•10⁻²³ J/K

KE(ave) = υ•N₀•3kT/2

KE(bullet)=mv²/2

υ• N₀•3kT/2= mv²/2

T= mv²/3k• υ• N₀=

=7.7•10⁻³•650²/3• 1.38•10⁻²³•2.2•6.022•10²³=287 K

- physics -
**kraze**, Friday, June 19, 2015 at 12:23am
formula to use is:

T= (mv^2)/u No 3k

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