The term mole is used in chemistry to define an amount of a substance. For example, a mole of glucose, blood sugar, weighs 180.16 grams. A common concentration unit for solutions is moles of substance per liter of solution. We abbreviate this with the symbol M. For example, 0.28M glucose really means 0.28 moles of glucose per liter of solution. How many milliliters of 0.28M glucose will contain 1.9 grams of glucose?
volume(L) = moles ÷ M(moles/L)
1.9g * 1mole/180.16g / .28mole/L = .0377L = 37.7mL
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To determine the volume in milliliters of a 0.28M glucose solution that contains 1.9 grams of glucose, we can use the concept of molarity and convert grams to moles, then use the molar concentration to calculate the volume.
First, we need to convert the mass of glucose to moles. We can do this by using the molecular weight of glucose, which is 180.16 g/mol.
Number of moles = Mass of glucose (g) / Molecular weight of glucose (g/mol)
Plugging in the values,
Number of moles = 1.9 g / 180.16 g/mol ≈ 0.01055 mol
Now, we can use the molar concentration formula to calculate the volume.
Molarity (M) = Moles of solute / Volume of solution (L)
We can rearrange the formula to solve for the volume:
Volume of solution (L) = Moles of solute / Molarity (M)
Plugging in the values,
Volume of solution (L) = 0.01055 mol / 0.28 M ≈ 0.0377 L
However, the question asks for the volume in milliliters (mL), so we need to convert the volume from liters to milliliters.
Volume of solution (mL) = Volume of solution (L) × 1000 mL/L
Plugging in the values,
Volume of solution (mL) = 0.0377 L × 1000 mL/L ≈ 37.7 mL
Therefore, approximately 37.7 milliliters of a 0.28M glucose solution will contain 1.9 grams of glucose.