Posted by Melanie on Monday, January 28, 2013 at 8:50am.
It travels up untils its vertical velocity is zero. That happens after t = 7.7/g = 0.785 seconds. (That answers your second question). During that time, it moves upward
t*Vaverage =
(1/2)*(7.7)*(0.785) = 3.02 m
Add that to the height from which it was released, and you get 3.80 meters
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