Thursday

April 24, 2014

April 24, 2014

Posted by **Miranda G.** on Sunday, January 27, 2013 at 9:17pm.

- Math, volume -
**Damon**, Sunday, January 27, 2013 at 9:50pmI assume the cylinder is outside the sphere

In that case subtract

pi r^2 h - (4/3)pi r^3

if the sphere fits exactly in the cylinder then

D = h = 2 r

and we have

2 pi r^3 - (4/3) pi r^3

= (2/3) pi r^3

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