A current-carrying conductor of length 0.8 m is placed perpendicular to the direction of the magnetic field of 0.6 Tesla. What is the value of the current in the conductor if the conductor experiences a force of 1.2 N?

To find the value of the current in the conductor, we can use the formula for the magnetic force experienced by a current-carrying conductor:

F = BIL sin(θ)

Where:
- F is the force experienced by the conductor
- B is the magnetic field strength
- I is the current in the conductor
- L is the length of the conductor
- θ is the angle between the direction of the current and the magnetic field

In this case, we are given:
- F = 1.2 N
- B = 0.6 T
- L = 0.8 m

Let's assume that the conductor is placed in such a way that the current is perpendicular to the magnetic field, which means θ = 90 degrees.

Now we can rearrange the formula to solve for the current I:

I = F / (BL sin(θ))

Substituting the given values:

I = 1.2 N / (0.6 T * 0.8 m * sin(90°))

Since sin(90°) = 1, the equation simplifies to:

I = 1.2 N / (0.6 T * 0.8 m)

Calculating the value:

I = 1.2 N / 0.48 Tm

I = 2.5 A

Therefore, the value of the current in the conductor is 2.5 Amperes.