A current-carrying conductor of length 0.8 m is placed perpendicular to the direction of the magnetic field of 0.6 Tesla. What is the value of the current in the conductor if the conductor experiences a force of 1.2 N?
To find the value of the current in the conductor, we can use the formula for the magnetic force experienced by a current-carrying conductor:
F = BIL sin(θ)
Where:
- F is the force experienced by the conductor
- B is the magnetic field strength
- I is the current in the conductor
- L is the length of the conductor
- θ is the angle between the direction of the current and the magnetic field
In this case, we are given:
- F = 1.2 N
- B = 0.6 T
- L = 0.8 m
Let's assume that the conductor is placed in such a way that the current is perpendicular to the magnetic field, which means θ = 90 degrees.
Now we can rearrange the formula to solve for the current I:
I = F / (BL sin(θ))
Substituting the given values:
I = 1.2 N / (0.6 T * 0.8 m * sin(90°))
Since sin(90°) = 1, the equation simplifies to:
I = 1.2 N / (0.6 T * 0.8 m)
Calculating the value:
I = 1.2 N / 0.48 Tm
I = 2.5 A
Therefore, the value of the current in the conductor is 2.5 Amperes.