Posted by Mandy on Sunday, January 27, 2013 at 6:44pm.
I. 71. The mode, by definition is the answer that appears most frequently.
II. The midrange is 64, which is by definition the arithmetic mean of the largest and the smallest values in a sample or other group. The range is 55. Let H = highest score, and L = lowest score. Then,
(H+L)/2 = 64
H-L = 55
Use algebra to solve for H and L
III. See part II
IV
In general terms, the chebyshev’s theorem states that at least (1- 1/k2) of the elements of any distribution lie
Within k standard deviations of the mean (where k = a number greater than 1). 30 is 24 less than the mean of 54; 78 is 24 more than 54; 24 is 3 times the standard deviation of 8; So k = 3, so at least 1 - 1/9, or at least 8/9 of the total 53 scores lie between 30 and 78.
V. 22 is 4 standard deviations below the mean of 54, and 86 is 4 standard deviations above 54; According to the empirical rule, 68% of the values lie within 1 standard deviation of the mean, 95% of the values lie within 2 standard deviations of the mean, and 99.73% lie within 3 standard deviations of the mean. So even more than 99.73% would lie within 4 standard deviations of the mean; this number has to be a whole number, so the entire set of 53 scores lies within this range.
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