Wednesday

April 16, 2014

April 16, 2014

Posted by **Mike** on Sunday, January 27, 2013 at 6:16pm.

lim 8^h-1/h

h->0

- Calculus -
**Damon**, Sunday, January 27, 2013 at 6:30pmIf you really mean what you typed

8^h - (1/h)

h 8^h / h - 1/h

[h 8^h - 1 ]/h

8^0 = 1 so

[0 - 1] /0 --- > oo

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