Posted by Mike on .
Estimate the following limit by substituting smaller and smaller values of h.
lim 8^h1/h
h>0

Calculus 
Damon,
If you really mean what you typed
8^h  (1/h)
h 8^h / h  1/h
[h 8^h  1 ]/h
8^0 = 1 so
[0  1] /0  > oo