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posted by Mike Sunday, January 27, 2013 at 6:16pm.
Estimate the following limit by substituting smaller and smaller values of h. lim 8^h-1/h h->0
If you really mean what you typed 8^h - (1/h) h 8^h / h - 1/h [h 8^h - 1 ]/h 8^0 = 1 so [0 - 1] /0 --- > oo
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