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September 2, 2014

September 2, 2014

Posted by **Em** on Sunday, January 27, 2013 at 3:16pm.

(a) Find the average value of f.

(b) Find c such that f(average) = f(c).

- Math -
**Reiny**, Sunday, January 27, 2013 at 4:41pmaverage value

= 1/(3-0) ∫(2x^2 - 8x + 9) dx from x = 0 to x = 3

= (1/3) [(2/3)x^3 - 4x^2 + 9x[ from 0 to 3

= (1/3) (18 - 36 + 27 - 0 )

= 3

b)

f(c) = f(3)

2c^2 - 8c + 9 = 18 - 16 + 9

2c^2 - 8c -2 = 0

c^2 - 4c - 1 = 0

c = (4 ± √20)/2

= 2 ± √5

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