Thursday

July 31, 2014

July 31, 2014

Posted by **Em** on Sunday, January 27, 2013 at 3:10pm.

y = sin x and y = x^2 - x, 0 ≤ x ≤ 2.

- math -
**Reiny**, Sunday, January 27, 2013 at 4:31pmI made a rough sketch and it looks like the sine curve and the parabola intersect at x=0 and somewhere around 1.6

Not sure what methods you have at your disposal to solve x^2 - x - sin(x) = 0

but we will need that second value of x at that intersection.

Are you familiar with Newton's method?

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