Posted by Em on Sunday, January 27, 2013 at 3:10pm.
I made a rough sketch and it looks like the sine curve and the parabola intersect at x=0 and somewhere around 1.6
Not sure what methods you have at your disposal to solve x^2 - x - sin(x) = 0
but we will need that second value of x at that intersection.
Are you familiar with Newton's method?
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