Posted by Anonymous on Sunday, January 27, 2013 at 12:57pm.
Take the ring of the radius ‘r’ and the width ‘dr’ on the disc.
The electric field at the distance ‘x’ from the center of the disc is
dE=x•dq/4πε₀• {sqrt(r²+x²)}³,
where dq=σ•dA = σ•2•π•r•dr.
E(x)=
=intergral(limits: from 0 to R)
{σ•2•π•r•x•dr/ 4πε₀• [sqrt(r²+x²)]³ =
=(σx/2ε₀)•{(1/x)- [1/sqrt(R²+x²)]}.
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