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March 31, 2015

March 31, 2015

Posted by **cz** on Sunday, January 27, 2013 at 2:39am.

- u of s -
**drwls**, Sunday, January 27, 2013 at 8:17amNote that they only ask for the heat transfer due to radiation. Use the Stefan-Boltzmann law.

The can's temperatuire will be 373 K, initially.

The room temperature is 293 K.

Q = M*C*dT/dt

You want the cooldown rate dT/dt

Q = A*sigma*(373^4 - 293^4)

C = 4184 J/kg*K is the specific heat of water

A is the can's outside arwea in m^2

sigma is the Stefan-Boltzmann constant. Assume can and room wall emissivity = 1.

M is the water mass

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