Nila is now x years old. 3 years ago, her brother ricky was twice as old as she. Write ricky's age 10 years from now in terms of x.
(with solution pls... thanks...)
Three years ago:
Nila's age --- x-3
Ricky's age --- 2(x-3)
present:
Nila: --- x
Ricky -- 2(x-3) + 3 = 2x -6 + 3 = 2x - 3
in 10 years:
Nila --- x+10
ricky ---- 2x-3+10 = 2x + 7
To find Ricky's age 10 years from now in terms of x, we need to first determine Nila's current age. From the given information, we know that 3 years ago Ricky was twice as old as Nila.
Let's assume Nila's current age is represented by x. Three years ago, Nila would have been (x - 3) years old. At that time, Ricky's age would have been twice that of Nila, so his age would have been 2 * (x - 3) years old.
Now, to determine Ricky's age 10 years from now, we need to add 10 years to his current age. So, Ricky's age 10 years from now can be expressed as:
2 * (x - 3) + 10
Simplifying the expression further, we have:
2x - 6 + 10
2x + 4
Therefore, Ricky's age 10 years from now, in terms of x, is 2x + 4.