A flight attendant pulls her 66 N flight bag a distance of 318 m along a level airport floor at a constant velocity. The force she exerts is 43 N at an angle of 52° above the horizontal.
(a) Find the work she does on the flight bag.
(b) Find the work done by the force of friction on the flight bag.
(c) Find the coefficient of kinetic friciton between the flight bag and the floor.
This looks like homework dumping by the same using multiple names.
Use the standard work formula in this case.
66x318=n
n=sin 52
sin52=66x318
n=318x66
n/66=318
cos52= 318
318=Ff
To find the answers to these questions, we need to understand the concepts of work and friction.
(a) Work done by the flight attendant on the flight bag:
The work done is equal to the force applied multiplied by the displacement traveled in the direction of the force. Since the flight attendant pulls the bag horizontally, the angle of 52° above the horizontal is not relevant to the work done in this case.
The work done (W) can be calculated using the formula:
W = force * distance * cos(angle)
Given:
Force applied (F) = 43 N
Distance traveled (d) = 318 m
Angle (θ) = 0° (since the force is horizontal)
Using the formula, we can calculate the work done:
W = 43 N * 318 m * cos(0°)
W = 43 N * 318 m * 1 (cos(0°) = 1)
W = 13,674 J (Joules)
Therefore, the work done by the flight attendant on the flight bag is 13,674 Joules.
(b) Work done by the force of friction on the flight bag:
The work done by the force of friction is equal to the product of the frictional force and the displacement. In this case, the force of friction acts in the opposite direction to the applied force, so it is negative.
To calculate the work done by friction, we need to find the frictional force first.
Given:
Force applied (F) = 43 N
Since the bag moves at a constant velocity, the horizontal component of the force applied must be equal to the force of friction:
Force of friction (F_friction) = 43 N * cos(52°)
Using the formula for work, we can calculate the work done by friction:
W_friction = -F_friction * d
W_friction = -(43 N * cos(52°)) * 318 m
Therefore, the work done by the force of friction on the flight bag is -8,046 J (Joules) (negative since it opposes the motion).
(c) Coefficient of kinetic friction between the flight bag and the floor:
The coefficient of kinetic friction (μ_k) can be calculated using the equation:
μ_k = F_friction / N
where F_friction is the force of friction and N is the normal force.
The normal force (N) is equal to the weight of the bag, which can be calculated as:
N = mass * gravity
where gravity is the acceleration due to gravity (9.8 m/s^2) and mass is the mass of the bag.
Since the bag is at a constant velocity, the force of friction is given by:
Force of friction (F_friction) = 43 N * cos(52°)
Substituting these values, we can find the coefficient of kinetic friction:
μ_k = (43 N * cos(52°)) / (mass * gravity)
Please provide the mass of the bag to find the coefficient of kinetic friction between the flight bag and the floor.