Homework Help: physics

Posted by Lauren Miller on Saturday, January 26, 2013 at 9:27pm.

A spring has a force constant of 410.0 N/m.
(a) Determine the potential energy stored in the spring when the spring is stretched 4.13 cm from equilibrium.
(b) Determine the potential energy stored in the spring when the spring is stretched 3.06 cm from equilibrium.
(c) Determine the potential energy stored in the spring when the spring is unstretched.

physics - Henry, Monday, January 28, 2013 at 4:44pm
a. F = 410N/m * 0.0413m = 16.93 N.

PE = F*d = 16.93 * 0.0413 = 0.7 Joules.

b. Same procedure as a.

c. F = 410N/m * 0 = 0.
PE = F * d = 0*0 = 0.

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