Posted by Kelsey on Saturday, January 26, 2013 at 5:47pm.
How would you solve the following I'm stumped..
- Algebra 2 - MathGuru, Saturday, January 26, 2013 at 5:56pm
First, set each equation equal to 0:
1. 2x^2 + 4x - 30 = 0
2. x^3 + 6x^2 + 8x = 0
Try to factor when possible:
1. (2x - 6)(x + 5) = 0
2. x(x^2 + 6x + 8) = 0
x(x + 2)(x + 4) = 0
Set each factor equal to 0:
1. 2x - 6 = 0
x + 5 = 0
2. x = 0
x + 2 = 0
x + 4 = 0
Can you take it from here to find the solutions for x in both problems?
I hope this explanation helps.
- Algebra 2 - Kelsey, Saturday, January 26, 2013 at 5:58pm
Yes thank you!
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