Thursday

April 17, 2014

April 17, 2014

Posted by **Kelsey** on Saturday, January 26, 2013 at 5:47pm.

1. 2x^2(squared)=30-4x

2. X^3(cubed)+8x=-6x^2(squared)

Thanks!

- Algebra 2 -
**MathGuru**, Saturday, January 26, 2013 at 5:56pmFirst, set each equation equal to 0:

1. 2x^2 + 4x - 30 = 0

2. x^3 + 6x^2 + 8x = 0

Try to factor when possible:

1. (2x - 6)(x + 5) = 0

2. x(x^2 + 6x + 8) = 0

x(x + 2)(x + 4) = 0

Set each factor equal to 0:

1. 2x - 6 = 0

x + 5 = 0

2. x = 0

x + 2 = 0

x + 4 = 0

Can you take it from here to find the solutions for x in both problems?

I hope this explanation helps.

- Algebra 2 -
**Kelsey**, Saturday, January 26, 2013 at 5:58pmYes thank you!

**Related Questions**

integrated algebra - how can you solve x^2 - 3x = 0 i was using a formula as: x^...

Ninth grade - How would I solve this? I'm totally stumped and I need some help. ...

algebra - I am stumped!!! quadratic equation solve for x: xsq+16x+4=0 please ...

algebra - well i'm stumped. i can't figure out how to solve this. solve for (x,y...

Algebra - I am great at math but for some reason can not wrap my brain around ...

cubic function - I am absolutly stumped at how to solve this. I know for squared...

Algebra 2 w/Trigonometry - How would you solve the following problem: m-(m+4n)-...

Algebra - The following problem must be solved 3 different ways in which X=...

algebra URGENT HELP - analyze the graph of the following function solve R(x)=x(x...

How would you solve the following inequality - How would you solve the following...