Posted by **Kelsey** on Saturday, January 26, 2013 at 5:47pm.

How would you solve the following I'm stumped..

1. 2x^2(squared)=30-4x

2. X^3(cubed)+8x=-6x^2(squared)

Thanks!

- Algebra 2 -
**MathGuru**, Saturday, January 26, 2013 at 5:56pm
First, set each equation equal to 0:

1. 2x^2 + 4x - 30 = 0

2. x^3 + 6x^2 + 8x = 0

Try to factor when possible:

1. (2x - 6)(x + 5) = 0

2. x(x^2 + 6x + 8) = 0

x(x + 2)(x + 4) = 0

Set each factor equal to 0:

1. 2x - 6 = 0

x + 5 = 0

2. x = 0

x + 2 = 0

x + 4 = 0

Can you take it from here to find the solutions for x in both problems?

I hope this explanation helps.

- Algebra 2 -
**Kelsey**, Saturday, January 26, 2013 at 5:58pm
Yes thank you!

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