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March 1, 2015

March 1, 2015

Posted by **Funnyguy** on Saturday, January 26, 2013 at 1:37pm.

1) What is the speed of the red ball right before it hits the ground?

2)How long does it take the red ball to reach the ground?

3) What is the maximum height the blue ball reaches?

4)What is the height of the blue ball 1.9 seconds after the red ball is thrown?

5) How long after the red ball is thrown are the two balls in the air at the same height?

- Physics -
**Henry**, Sunday, January 27, 2013 at 8:49pm1. V^2 = Vo^2 + 2g*h.

V^2 = (1.3)^2 + 19.6*28 = 550.49

V = 23.5 m/s.

2. h = Vo*t + 0.5g*t^2 = 28 m.

1.3t + 4.9t^2 = 28

4.9t^2 + 1.3t -28 = 0

Use Quadratic Formula.

t - 2.26 s.

3. V^2 = Vo^2 + 2g*h.

h = 0.8 + (V^2-Vo^2)/2g.

h = 0.8 + (0-(24.7)^2)-19.6 = 31.93 m.

Above gnd.

4. T = 1.9-0.6 = 1.3 s. = Time in air.

h = Vo*t + 0.5g*t^2.

h = 24.7*1.3 + (-4.9)*(1.3)^2 = 23.8 m.

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