Tuesday

September 23, 2014

September 23, 2014

Posted by **brizett** on Saturday, January 26, 2013 at 12:19pm.

- physics -
**Henry**, Sunday, January 27, 2013 at 4:40pmd1 = 0.5g*t^2 = 30-3.2 = 26.8.

4.9t^2 = 26.8

t^2 = 5.47

t = 2.34 s. = Fall time of 1st stone.

The 2nd stone must fall 30 meters in

2.34 s.

d2 = Vo*t + 0.5g*t^2 = 30 m.

Vo*2.34 + 4.9(2.34)^2 = 30

2.34Vo + 26.83 = 30

2.34Vo = 30-26.83 = 3.17

Vo = 1.35 m/s. = Initial velocity of 2nd stone.

**Answer this Question**

**Related Questions**

Physics - While standing on a bridge 45.0 m above ground, you drop a stone from ...

Physics - While standing on a bridge 45.0 m above ground, you drop a stone from ...

physics - While standing on a bridge 45.0 m above ground, you drop a stone from ...

physics - While standing on a bridge 15.0 m above the ground, you drop a stone ...

physics - While standing on a bridge 15.0 m above the ground, you drop a stone ...

physics - While standing on a bridge 15.0 m above the ground, you drop a stone ...

Physics - While standing on a bridge 18.3 m above the ground, you drop a stone ...

Physics - While standing on a bridge 19.1 m above the ground, you drop a stone ...

physics - While standing on a bridge 18.5 m above the ground, you drop a stone ...

college physics - While standing on a bridge 15.0 m above the ground, you drop a...