Posted by Amy on Saturday, January 26, 2013 at 3:03am.
force on each = Q E
= 5 *10^-6 * 5 * 10^3 = 25 * 10^-3 N
torque resulting from each = F D
= 25 * 10^-3 * 2 = 50 * 10^-3 Nm
both give same sign torque so total torque = 100 *10^-3 Nm
= 0.1 Nm
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