Posted by anonymous on Saturday, January 26, 2013 at 2:55am.
s = initial speed
u = horizontal speed = s cos 26 = .899 s
Vi = initial speed up = s sin 26 = .438 s
It is not clear to me what your units are. If feet use g = 32 ft/s^2. If meters use g = 9.81 m/s^2. I assume from the 355 that you are using feet.
u is constant during the flight
d = u t
355 = .899 s t
so t = 395/s
now the vertical problem
for half of time t the ball is going up and the vertical speed is zero at the top
v = Vi - 32 * time rising
0 = .438 s - 32 (t/2)
16 t = .438 s
t = .0274 s
so we have two equations for t
395/s = .0274 s
s^2 = 14429
so
s = 120 ft/s
now for height
t = .0274 s
t = 3.29 seconds in the air
so 1.65 seconds rising
initial speed up = 120 sin 29 = 58.2
so average speed up = 58.2/2 = 29.1
h = 1.65 * 29.1 = 48 feet
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