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October 1, 2014

October 1, 2014

Posted by **anonymous** on Saturday, January 26, 2013 at 2:55am.

What was the initial speed of the ball?

How high does the ball rise above the point where it struck the bat?

- physics -
**Damon**, Saturday, January 26, 2013 at 5:12ams = initial speed

u = horizontal speed = s cos 26 = .899 s

Vi = initial speed up = s sin 26 = .438 s

It is not clear to me what your units are. If feet use g = 32 ft/s^2. If meters use g = 9.81 m/s^2. I assume from the 355 that you are using feet.

u is constant during the flight

d = u t

355 = .899 s t

so t = 395/s

now the vertical problem

for half of time t the ball is going up and the vertical speed is zero at the top

v = Vi - 32 * time rising

0 = .438 s - 32 (t/2)

16 t = .438 s

t = .0274 s

so we have two equations for t

395/s = .0274 s

s^2 = 14429

so

s = 120 ft/s

now for height

t = .0274 s

t = 3.29 seconds in the air

so 1.65 seconds rising

initial speed up = 120 sin 29 = 58.2

so average speed up = 58.2/2 = 29.1

h = 1.65 * 29.1 = 48 feet

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