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Posted by on Saturday, January 26, 2013 at 12:11am.

The height (in feet) at time t (in seconds) of a small weight oscillating at the end of a spring is given below.
h(t) = 0.2 cos(2t)

(a) Calculate the weight's average velocity over the time intervals [1, 2] and [5, 7].

  • Calculus - , Saturday, January 26, 2013 at 3:40am

    v = dh/dt = -0.4 sin(2t)

    average v from t = 1 to t = 2 is
    (Integral of v dt from 1 to 2)/(2-1)
    = [h(2)-h(1)]/(2 -1) = [-.1307 -(-0.0832)] = -0.0475 ft/s

    You can do the other interval yourself

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