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Find the arc length given the equation y=(x^4/8)+(1/4x^2) [1,3]

  • Calculus - ,

    Do you mean between x = 1 abd x = 3?

    Is the second term 1/(4x^2) or (1/4)x^2?

  • Calculus - ,

    Yes between the interval x=1 and x=3 and in the second term it is 1/(4x^2)

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