Friday

April 18, 2014

April 18, 2014

Posted by **Anonymous** on Friday, January 25, 2013 at 6:55pm.

1. limit as x goes to POSITIVE infinity

(10x+8)/(7x^2-3x+5)

2. as x goes to NEGATIVE infinity

(10x+8)/(7x^2-3x+5)

- Calculus -
**Damon**, Friday, January 25, 2013 at 7:22pm10 x/7x^2 -->10/7x ---> oo

-10 |x | /7 |x|^2 --> -10/7 |x| --> -oo

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